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[🐉 백준 7단계] 문자열Algorithm/케로베로스 2020. 12. 12. 11:34반응형
백준 7단계
문자열
11654.
print(ord(input()))
11720.
n = int(input()) a = str(input()) s = 0 for i in a: i = int(i) s += i print(s)
10809.
import string alpha = list(string.ascii_lowercase) answer = [] word = input() for a in alpha: if a in word: answer.append(str(word.index(a))) else: answer.append('-1') print(' '.join(answer))
2675.
t = int(input()) for _ in range(t): a, b = input().split() answer = '' for i in b: answer += i*int(a) print(answer)
1157.
n = input() d = {} for i in n: i = i.upper() if i not in d: d[i] = 1 else: d[i] += 1 m = max(d.values()) count = 0 answer = '' for k, c in d.items(): if m == c: count += 1 answer += k if count == 1: print(answer) else: print('?')
1152.
print(len(list(input().split())))
2908.
a, b = input().split() new_a = '' new_b = '' for i in range(len(a)-1, -1, -1): new_a += a[i] new_b += b[i] if new_a > new_b: print(int(new_a)) else: print(int(new_b))
* 더 간단하게 하는 방법
a = int(a[::-1]) b = int(b[::-1])
5622.
time = [i+2 for i in range(0,10)] n = input() count = 0 for i in n: if i in ('A','B','C'): count += time[1] elif i in ('D', 'E', 'F'): count += time[2] elif i in ('G', 'H', 'I'): count += time[3] elif i in ('J', 'K', 'L'): count += time[4] elif i in ('M', 'N', 'O'): count += time[5] elif i in ('P', 'Q', 'R', 'S'): count += time[6] elif i in ('T', 'U', 'V'): count += time[7] elif i in ('W', 'X', 'Y', 'Z'): count += time[8] else: count += 2 print(count)
2941.
c = ['c=', 'c-', 'dz=', 'd-', 'lj', 'nj', 's=', 'z='] n = input() count = 0 answer = 0 for i in c: if i in n: answer += n.count(i) n = n.replace(i, ' ') n = n.replace(' ', '') answer += len(n) print(answer)
1316.
t = int(input()) count = t for _ in range(t): n = input() s = set(n[0]) for i in range(1, len(n)): if n[i] != n[i-1] and n[i] in s: count -= 1 break else: s.add(n[i]) print(count)
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